Contact us
Choose a category below so we can get back to you as quickly as possible.
你的題目是不是(X²;-2X-3)/(2X²;2X 1)?若是,則設y=(X²;-2X-3)/(2X²;2X 1),得y(2X²;2X 1)=X²;-2X-3,整理得,(2y-1)x²;+(2y+2)x+y+3=0,看作是關於x的2次函數,則△=(2y+2)²;-4×(2y-1)(y+3)≥0,化簡得-y²;-4y+4≥0,解得y∈(-2-2√(2),-2+2√(2))
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.