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設兩個正整數根為:x1,x2,則 x1+x2=p,x1x2=q 因為q為質數, 所以x1=1,x2=q;或x2=1,x1=q 總之x1+x2=1+q=p, 如果q為奇質數,則1+q為偶數,即p為偶數且p>2,與p為質數衝突 所以q=2,p=3.
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