X / 3 + Y / 4 + Z / 5 = 1 / 3 find (XY + XZ + YZ) / (x ^ 2 + y ^ 2 + Z ^ 2)= How much is it

X / 3 + Y / 4 + Z / 5 = 1 / 3 this is a ternary linear equation, we can't solve the specific x, y, Z, so we can assume two of them and find the third number, so we can assume y = 0 and z = 0 to get: x = 1, so (XY + XZ + YZ) / (x ^ 2 + y ^ 2 + Z ^ 2) = 1

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