Finding the extremum of function y = (1 + 2x) e ^ x That's - 3 / 2
Y '= 2xe ^ x + (1 + 2x) e ^ x = (2x + 3) e ^ x E ^ x is always greater than zero, when x = - 3 / 2, y' = 0. So the extreme value Y (- 3 / 2) = - 2E ^ (- 3 / 2)
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