Finding the extremum of function y = 8x ^ 2-12x ^ 2 + 6x + 1

If y = - 4x ^ 2 + 6x + 1 and its derivative is 0, the abscissa of the extreme point can be obtained
Y '= - 8x + 6 = 0, x = 3 / 4
Take x = 3 / 4 into y to get y = - 4 * (3 / 4) ^ 2 + 6 * 3 / 4 + 1 = - 9 / 4 + 18 / 4 + 1 = 13 / 4

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