Finding the extremum of function y = 8x ^ 3-12x ^ 2 + 6x + 1

y=8x^3-12x^2+6x+1
y!=24x^2-24x+6=6(2x-1)^2 ,y!=0 ,x=1/2 x0 ,x>1/2 ,y!>0
So the function has no extremum

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