How to find the plane normal vector, please explain the specific method!

Vector Ba = (1,0, - 1), vector BC = (0,1,1)
Try to find the vector p = (a, y, z)
P is perpendicular to Ba and BC
x-z=0,y+z=0
x=-y=z
Take a set of nonzero solutions, x = 1, y = - 1, z = 1
Normal vector (1, - 1,1)
After knowing the two vectors in the plane, they are all vertical

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