Finding the derivative of Ln (x + √ 1 + x square)

Finding the derivative of Ln (x + √ 1 + x square)

Derivative = {1 / [x + √ (1 + X & # 178;)]} * [1 + X / √ (1 + X & # 178;)]
={1/[x+√(1+x²)]}*[x+√(1+x²)]/√(1+x²)
=1/√(1+x²)