Why is the direct answer to the derivative problem of compound function y = radical (1 + ln ^ 2x) y '= 1 / 2 · 1 / radical (1 + ln ^ 2x)^ Derivative problem of compound function Y = root (1 + ln ^ 2x) Why is the answer y '= 1 / 2 · 1 / radical (1 + ln ^ 2x) · (1 + ln ^ 2x)' Why can't you peel it down like u = 1 + V, v = ln ^ m, M = 2x when you peel it to 1 + ln ^ 2x? That's y'u'v'm ', but that's not right

Why is the direct answer to the derivative problem of compound function y = radical (1 + ln ^ 2x) y '= 1 / 2 · 1 / radical (1 + ln ^ 2x)^ Derivative problem of compound function Y = root (1 + ln ^ 2x) Why is the answer y '= 1 / 2 · 1 / radical (1 + ln ^ 2x) · (1 + ln ^ 2x)' Why can't you peel it down like u = 1 + V, v = ln ^ m, M = 2x when you peel it to 1 + ln ^ 2x? That's y'u'v'm ', but that's not right

The answer is just not complete,
You can just calculate (1 + ln ^ 2x) 'again,
(1+ln^2x)' =2lnx /x
So the result is to multiply your formula by 2lnx / X