Given the intersection (2,0) of quadratic function image and X axis (- 1,0), and the intersection (0, - 1) of quadratic function image and Y axis | Math enthusiast | Mathematical art

Given the intersection (2,0) of quadratic function image and X axis (- 1,0), and the intersection (0, - 1) of quadratic function image and Y axis

Let the analytic formula of quadratic function be y = a (X-2) (x + 1), substitute the point (0, - 1), get - 1 = a (0-2) (0 + 1), get a = 12; so the analytic formula of quadratic function is y = 12 (X-2) (x + 1); y = 12 (X-2) (x + 1) = 12 (X-12) 2-98, vertex coordinates are (12, - 98)

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