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設二次函數解析式為y=a(x-2)(x+1),代入點(0,-1),得-1=a(0-2)(0+1),解得a=12;所以二次函數解析式為y=12(x-2)(x+1);y=12(x-2)(x+1)=12(x-12)2-98,頂點座標為(12,-98).
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