Given the inverse proportion function y = k of X, when x = - 1 / 3, y = - 6, find the analytic solution of the inverse proportion function. Thank you
Given the inverse proportion function y = K / x, when x = - 1 / 3, y = - 6, find the analytic expression of the inverse proportion function
By substituting x = - 1 / 3, y = - 6 into the function, we get - 6 = K / (- 1 / 3) = - 3k, so k = 2, that is, the analytic formula is y = 2 / X
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