If the image of the inverse scale function passes through points (1, 3) (1) find the analytic expression of the inverse scale function; (2) find the intersection coordinates of the primary function y = 2x + 1 and the image of the inverse scale function

(1) Let the analytic expression of inverse proportion function be y = KX (K ≠ 0). From the image, we can see that the analytic expression of inverse proportion function is y = 3x (2). From the meaning, we can get y = 3xy = 2x + 1, x = 1y = 3, x = − 32y = − 2, so the intersection coordinates of image are (1,3), (- 32, - 2)

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