As shown in the figure, the image of the first-order function y = KX + 2 and the inverse scale function y = K / X intersects a (4, m)
This is very simple! The point of intersection (4, m) must be on the graph of first-order function, so, 4K + 2 = M. in addition, this point is also on the graph of inverse scale function, so, M = K / 4, two simultaneous equations can be solved, M = - 2 / 15
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- 1. If the inverse scale function y = K / X intersects with the image of the first-order function y = KX + 2, then the value range of K is Such as the title
- 2. If there is an intersection point between the image of inverse scale function y = 2 / X and the image of primary function y = kx-4, the value range of K is obtained Hope as soon as possible
- 3. It is known that the ordinate of an intersection of the inverse scale function y = KX and the linear function y = 2x + k is - 4, then the value of K is -___ .
- 4. As shown in the figure, it is known that the two vertices of RT △ OAB are a [6,0], B [0,8], O is the origin, and △ OAB rotates 90 ° clockwise around point A. point O arrives at point o ', and point B arrives at point B' (1) Finding the coordinates of point B 丿 (2) Finding the analytic expression of the function corresponding to the line ab 丿
- 5. As shown in the figure, it is a part of the image of an inverse scale function, and points a (1,10) and B (10,1) are its endpoints. (1) find the analytic expression of the function, and write out the value range of the independent variable x; (2) please give an example of life that can be described by the functional relationship of this problem
- 6. Given that the vertex of the parabola is (- 1,4), and the length of the line segment cut on the x-axis is 6, the analytical formula of the parabola is obtained
- 7. The volume of the geometry obtained by rotating the curve y = X2 (0 ≤ y ≤ 1) around the Y axis
- 8. Find the area a of the figure enclosed by the curve y = e ^ x, y = 2 and x = 0, and the volume of one revolution around the Y axis Using the knowledge of definite integral,
- 9. The area of the figure enclosed by the curve y = x & # 178; - 1 and X axis is equal to
- 10. The area of the figure enclosed by the curve expressed by the equation | x | + | y | = 1 is () A. 2B. 2C. 1D. 4
- 11. It is known that the intersection point of the image with the inverse scale function y = K / X and the linear function y = MX + n is a3,4 And the distance from the intersection of the image of the first-order function and the x-axis to the origin is 5 Finding two analytic expressions Find the coordinates of another point and determine what type of angle AOB is
- 12. If the image of a function of degree passes through points (3,5) and (- 4, - 9), then the coordinates of the intersection of the image of the function and the y-axis are______ .
- 13. If the image of a function of degree passes through points (3,5) and (- 4, - 9), then the coordinates of the intersection of the image of the function and the y-axis are______ .
- 14. Given that the image of the first-order function passes through a point (1,2), and the product of the abscissa of the intersection of the image and the x-axis and the ordinate of the y-axis is 9, the first-order function can be obtained
- 15. Given that the image of a function passes through a point (1,2), and the product of the abscissa of the intersection of the image and the X axis and the ordinate of the intersection of the image and the Y axis is 9, the analytic expression of the function is obtained
- 16. It is known that the intersection point of the image and the Y-axis of the linear function y = (3a-7) x + A-2 of X is above the x-axis
- 17. For the first-order function y = (3a-7) x + A-2 of X, the intersection of the image and Y axis is below x, and Y decreases with the increase of X, then the value range of a is______ .
- 18. It is known that the intersection of the image of y = (3a-7) x + A + 1 and the Y axis is above the X axis It is known that the intersection of the image of the first-order function y = (3a-7) x + A + 1 and the y-axis is above the x-axis, and when X1 is less than x2 The corresponding function value y satisfies that Y1 is greater than Y2, and the value range of a is obtained
- 19. The image of a given function passes through the intersection of the line y = - x + 1 and the X axis And the ordinate of the point of intersection with the Y axis is - 2, so we can find the analytic expression of this first-order function
- 20. The image of the linear function y = x + 3 and the area of the triangle surrounded by the x-axis and y-axis are