If the inverse scale function y = K / X intersects with the image of the first-order function y = KX + 2, then the value range of K is Such as the title

Simultaneous y = K / X
y=kx+2
We get KX ^ 2 + 2x-k = 0
If there is an intersection point, the equation has a solution
Δ=4+4K^2
Obviously, whatever the value of K, Δ is greater than 0
The range of K is a set of real numbers

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