F (x) is an odd function defined on R, x > 0 is, f (x) = x + LNX, the number of real roots of the equation f (x) = 0 Multiple choice, just give me an answer

F (x) is an odd function defined on R, x > 0 is, f (x) = x + LNX, the number of real roots of the equation f (x) = 0 Multiple choice, just give me an answer

If f (x) is an odd function defined on R, then f (- x) = - f (x)
So f (0) = 0
It is shown that 0 is a real root of the equation f (x) = 0;
x> 0, f (x) = x + LNX
When x0, there is only one real solution x0, and 0