It is known that f (x) = lnx1 + X − LNX, and f (x) has the maximum value at x = x0. The correct sequence numbers in the following expressions are: ① f (x0) < x0; ② f (x0) = x0; ③ f (x0) > x0; ④ f (x0) < 12; ⑤ f (x0) > 12 A. ①④B. ②④C. ②⑤D. ③⑤

If G (x) = x + 1 + LNX (1 + x) 2, then the function has a unique zero point, that is, x0, ■ - x0-1 = lnx0 ｜ f (x0) = (− x0 − 1) · 1 − 1 − X01 + x0 = x0, that is, ② correct f (x0) − 12 = − 2x0lnx0 − (1 + x0) 2 (1 + x0) ∧ - x0-1 = lnx0, ｜ f (x0) − 12 = (...)

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