Find the area of the plane figure surrounded by the following curve X = √ X and the line y = 0, x = 1, x = 2

Find the area of the plane figure surrounded by the following curve X = √ X and the line y = 0, x = 1, x = 2

The problem seems to be wrong, it should be x under y = radical, DS = YDX = x ^ 1 / 2DX, s = SX ^ 1 / 2DX, integral interval is [1,2] let the radical x = t, x = T ^ 2, s = s2t ^ 2DT = 2 / 3sdt ^ 3, integral interval is [1, radical 2] s = 2 / 3 [(radical 2) ^ 3-1 ^ 3] = (4 radical 2-1) / 3