Given that the Quasilinear of the parabola y2 = 2px coincides with the left quasilinear of the hyperbola x2-y2 = 2, the focal coordinate of the parabola is______ .
By sorting out the hyperbolic equation, it is found that the left quasilinear equation of the hyperbola is x = - A2C = - 1, the Quasilinear equation of the parabola is x = - 1, P = 2, the focal coordinate of the parabola is (1, 0), so the answer is (1, 0)
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- 7. What is the intersection coordinate of parabola y = - 2x ^ 2-x + 3 and Y axis? What is the intersection coordinate of parabola y = - 2x ^ 2-x + 3 and X axis?
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- 11. If the left focus of hyperbola x23 − 16y2p2 = 1 is on the Quasilinear of parabola y2 = 2px, then the value of P is () A. 2B. 3C. 4D. 42
- 12. Given that the focus F of the parabola y2 = 2px (P > 0) is exactly the right focus of the hyperbola x2a2-y2b2 = 1 (a > 0, b > 0), and the hyperbola passes through the point (3a2p, B2P), then the asymptote equation of the hyperbola is () A. y=±2xB. y=±xC. y=±5xD. y=±153x
- 13. It is known that parabola y ^ 2 = 2px (P > 0) and hyperbola x ^ 2 (radical 2-1) ^ 2-y ^ 2 / b ^ 2 = 1 have the same focus F, point a is the focus of two curves, and AF is vertical On the x-axis, the line L and the parabola intersect at two different points c, D If the vector OC * od = m (M is a constant) and the line l only passes through a unique point, the value of M and this point can be obtained
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- 15. Find the area of the figure surrounded by X & # 178; + Y & # 178; = 2, X & # 178; + Y & # 178; = 4x, y = x, y = 0
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- 20. The volume of the body of revolution is obtained when the plane figure enclosed by the line y = √ (x-1), x = 4 and y = 0 rotates around the x-axis Review is urgent,