The Quasilinear equation of parabola x2 = y is______ .
Because the standard equation of parabola is: x2 = y, the focus is on the y-axis; so: 2p = 1, that is, P = 12, so: P2 = 14, the Quasilinear equation y = - P2 = − 14, that is, 4Y + 1 = 0. So the answer is: 4Y + 1 = 0
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