Area problem of space vector 1, a = (1,0,3) B = (- 1,0,2) calculate the area of the enclosed parallelogram 2, the equation of the plane parallel to the parallelogram and passing through the point (0,0,1) Sorry, it is a=(1,1,1) b=(-1,0,2)

Area problem of space vector 1, a = (1,0,3) B = (- 1,0,2) calculate the area of the enclosed parallelogram 2, the equation of the plane parallel to the parallelogram and passing through the point (0,0,1) Sorry, it is a=(1,1,1) b=(-1,0,2)

1. First, find the vector product a × B of vectors a and B = (1, - 3, - 1), and the area s of the parallelogram enclosed by vectors a and B = | a × B | = √ 11
2. The normal vector of the plane n = a × B = (1, - 3, - 1), so the plane equation is
1×(x－0)－3×(y－0)－1×(z－1)＝0
The results show that x-3y-z + 1 = 0