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In the circuit shown in the figure, r = 10 Ω, the power supply voltage remains unchanged. When a resistor with R1 = 30 Ω is connected in series in the circuit, the current representation is I1 = 0.25A. (1) calculate the power supply voltage? (2) How to connect the resistor in the figure if I2 = 1.2A? What is the resistance?
(1) If two resistors are connected in series and I = 0.25A, the voltage of the power supply is u = I (R1 + R2) = 0.25A × (10 Ω + 30 Ω) = 10V; (2) if the current representation is I2 = 1.2A, the total resistance in the circuit is r = ui2 = 10v1.2a = 253 Ω＜ 10 Ω, so a resistor R2, ∵ 1R = 1r1 + 1r2, ∵ 1253 Ω = 110 should be connected in parallel
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