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It is known that two parabola C1: y = x squared-4 and C2: y = x squared-2ax + B {a, B are constants} and The x-axis intersects at A1, B1 and A2, B2. The vertices are Q1 and Q2 respectively. It is known that the point P (a, b) is on the parabola C1 Try to explain the position relationship between two parabolas Judging the shape of quadrilateral a1q1q2a2 I hope I can help you. I really don't have any points now. I'm sorry
∵y1=x^2-4
y2=x^2-2ax+b
P (a, b) on Y1, B = a ^ 2-4 into Y2
y2=x^2-2ax+a^2-4
=(x-a)^2-4
(1) It can be seen from the analytical formula that Y2 is the result of Y1 moving a unit to the right
(2) The quadrilateral connected a1q1q2a2 is a parallelogram
(because A1A2 ‖ = q1q2)
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