It is known that the square of a straight line passing through point P (2,0) with a slope of 4 / 3 and a parabola y = 2x intersect at two points a and B. let the midpoint of line AB be M. Find the coordinates of point M. how to teach the students this problem, The answer seems to be m (41 / 16,3 / 4). How can I tell the students?

Let y = 4 / 3 (X-2) be substituted by Y & sup2; = 2x
Simplify 8x & sup2; - 41x + 32 = 0
Weida theorem X1 + x2 = 41 / 8
So m (x, y)
x=(x1+x2)/2=41/16
Substituting x = 41 / 16 into y = 4 / 3 (X-2)
y=4/3(41/16-2)=3/4
Point m (41 / 16,3 / 4)

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