Given that the inclination angle of the line passing through the focus of the parabola y ^ 2 = 4x is 60 degrees, then the distance from the vertex to the line is?

y^2=4x=2px
p=2.
Focus coordinates (1,0)
If the inclination angle is 60 degrees, the slope k = tan60 = root 3
So the linear equation is: y = radical 3 * (x-1)
That is, root 3x-y-root 3 = 0
The distance between vertex and line d = | - radical 3 | / radical (3 + 1) = radical 3 / 2

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