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What is the indefinite integral of COS ^ 2 (1-3x)
∫cos^2(1-3x)dx=-1/3∫cos^2(1-3x)d(1-3x)
=-1 / 6 ∫ (1 + Cos2 (1-3x)) / D (1-3x) = - 1 / 6 [(1-3x) + sin2 (1-3x) / 2] + C, C is the integral constant
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