∫ (2 + x) / √ (4-x∧2) DX to calculate indefinite integral

∫ (2 + x) / √ (4-x∧2) DX to calculate indefinite integral

∫ (2+x)/√(4-x²) dx
=∫ 2/√(4-x²) dx + ∫ x/√(4-x²) dx
=∫ 1/√(1-x²/4) dx + (1/2)∫ 1/√(4-x²) d(x²)
=arcsin(x/2) - √(4-x²) + C
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