∫ indefinite integral of 2x ^ 4 + 2x ^ 2 + 1 / x ^ 2 + 1dx!

∫ indefinite integral of 2x ^ 4 + 2x ^ 2 + 1 / x ^ 2 + 1dx!

Original formula = ∫ 2x ^ 4DX + ∫ 2x ^ 2DX + ∫ x ^ (- 2) DX + ∫ 1dx
=(2 / 5) x ^ 5 + (2 / 3) x ^ 3-1 / x + X + C
And in your formula, is 1 / x ^ 2 + 1 (1 / x ^ 2) + 1 or 1 / (x ^ 2 + 1)
If it is the latter, it is as follows:
Original formula = (2 / 5) x ^ 5 + (2 / 3) x ^ 3 + arctanx + C
I've added brackets to those scores. I'm afraid you'll get the following ones to the denominator