Finding the indefinite integral of 1 / e ^ x (1 + e ^ 2x)

∫ 1/e^x(1+e^2x) dx
= ∫ 1/e^x - e^x / (1+e^2x) dx
= - 1/e^x - ∫ 1/ (1+e^2x) de^x
= - 1/e^x - arctan(e^x) + C

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