Y = x (SiNx) (conx) derivation
y'=(xsinx)'cosx+(xsinx)(cosx)'=(sinx+xcosx)cosx+(xsinx)(-sinx)=sinxcosx+xcos2x
RELATED INFORMATIONS
- 1. Y = (SiNx) ^ 3 derivation
- 2. Given the function f (x) = - SiNx + SiNx + A, the square above that SiNx, if f (x) = O has a real number solution to find the range of a, if x belongs to R 1 (less than or equal to FX) less than or equal to ten fourths Help solve it
- 3. F (x) = the minimum positive period under the root sign (the square of SiNx to the fourth power of SiNx)
- 4. Is the maximum value of function y = 2 + SiNx 2 right or wrong
- 5. The maximum value of the function y = x-sinx on [π / 2, π]? Please indicate the reason,
- 6. What is the value of X, y = 1-2 / 3 SiNx take the maximum and minimum values? What are the maximum and minimum values
- 7. The maximum value of the function y = SiNx + 3cosx is () A. 1B. 2C. 3D. 2
- 8. As shown in the figure, what is the area of the triangle with a (0,3), B (1,0) and C (2,2) as vertices
- 9. As shown in the figure, triangle ABC is divided into triangle BDE and quadrilateral ACDE by line segment de. question: what is the area of triangle BDE that is the area of quadrilateral ACDE?
- 10. Two line segments divide the triangle into three triangles and a quadrilateral. As shown in the figure, if the areas of the three triangles are 3, 7 and 7 respectively, the shadow area is?
- 11. Y = SiNx (1 + 2cosx ^ 2) maximum, minimum
- 12. Integral (cosx) ^ 2 / (SiNx) ^ 2
- 13. Integral of (SiNx) ^ 2 (cosx) ^ 2
- 14. Syndrome: I = ∫ (0, √ (2 Π)) SiNx & #178; DX > 0
- 15. 2 ∫ sinx/1+x²dx=( ) -2
- 16. Calculate ∫ upper π lower 0 √ (1-sinx) DX steps!
- 17. If x is the minimum internal angle of a triangle, then the maximum value of the function y = SiNx + cosx + sinxcosx is () A. -1B. 2C. −12+2D. 12+2
- 18. X is the inner angle of the triangle, and sinxcosx = - 1 / 8, find the value of SiNx cos
- 19. For example, why arcsin (2x-1), arccos (1-2x), 2arctan radical (x / (1-x)) are all primitive functions of 1 / radical (x-x Square)? Please
- 20. Higher mathematics proves the identity 2arcsinx arccos (1-2x ^ 2) = 0 0 < x < 1