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2 ∫ sinx/1+x²dx=（ ） -2
Since SiNx is an odd function, 1 + X & # is an even function
The product of odd function and even function is still odd function
So according to the parity of definite integral
∫(- 2→2) sinx/(1 + x²) dx = 0
RELATED INFORMATIONS
- 1. Syndrome: I = ∫ (0, √ (2 Π)) SiNx & #178; DX > 0
- 2. Integral of (SiNx) ^ 2 (cosx) ^ 2
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