Given a = {(x, y) | x = √ 2 cosa, y = √ 2 Sina + m, a is a parameter} B = {{x, y) | x = t + 3, y = 3-T, t is a parameter} and a ∩ B ≠ & # 8709;, the value range of real number m is obtained

Given a = {(x, y) | x = √ 2 cosa, y = √ 2 Sina + m, a is a parameter} B = {{x, y) | x = t + 3, y = 3-T, t is a parameter} and a ∩ B ≠ & # 8709;, the value range of real number m is obtained

A = {(x, y) | x = √ 2 cosa, y = √ 2 Sina + m, a is a parameter}
x=√2 cosa,y=√2 sina + m
==>
x²+(y-m)²=2
A is the center of C (0, m), and √ 2 is the set of points on the radius circle
B = {{x, y) | x = t + 3, y = 3-T, t is a parameter}
x=t+3,y=3-t
==>X + y = 6, that is, x + y-6 = 0
B is the set of points on the line x + y-6 = 0
A ∩ B ≠ &;, the line and the circle C have a common point
The distance from C to the straight line is less than or equal to the radius
That is | M-6 | / √ 2 ≤ √ 2
∴|m-6|≤2
==>4≤m≤8
I hope I can help you, if you can