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What is the linear equation that is tangent to the square of the circle x + (Y-2) and the intercept on the two axes is equal (the intercept is not 0)? You can't square your cell phone! Exam, urgent!
The slope of the line is - 1
Let the line be y = - x + M
That is x + y-m = 0
Given the center of the circle (0,2), radius √ 2
Distance from center of circle to straight line = | 2-m | / √ 2 = √ 2
|2-m|=2
M = 0 or M = 4
Because the line is not the origin, m ≠ 0
So the line is x + y-4 = 0
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