Given the circle C (X-2) 2 + y2 = 2, if the line L is tangent to the circle and the intercept of the two axes is equal,

Given the circle C (X-2) 2 + y2 = 2, if the line L is tangent to the circle and the intercept of the two axes is equal,

When k = - 1, the equation of L is y = - x + m, that is, x + y-m = 0, the distance from the center of the circle (2,0) to the line L is equal to the radius, that is, | 2 + 0-m | / √ 2 = √ 2 | m-2 | = 2