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圓c(x-2)2+y2=2,切線l在兩坐標軸截距相等,那麼l的斜率k=-1或l過原點,當k=-1時,則l方程為y=-x+m即x+y-m=0圓心(2,0)到直線l的距離等於半徑,即|2+0-m|/√2=√2|m-2|=2解得m=0或m=4l方程為x+y=0或x+y-2=0若直線l過原點,…
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