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設切線方程 y+2=k(x-1) y=kx-k-2 kx-y-k-2=0 x^2+y^2-6x-2y+6=0 (x-3)^2+(y-1)^2=4 圓心(3,1)半徑2 圓心到切線的距離=2 2=|3k-1-k-2|/根(k^2+1) k=5/12 切線方程是 y=5(x-1)/12-2 顯然x=1也是切線
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