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直線的斜率為-1 設直線為y=-x+m 即x+y-m=0 已知圓心(0,2),半徑√2 圓心到直線的距離=|2-m|/√2=√2 |2-m|=2 m=0或m=4 因為直線不過原點,所以m≠0 所以直線為x+y-4=0
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