Tangent equation of circle x2 + y2 = 4 through M (radical 3,1)?

The center O (0,0) of circle x2 + y2 = 4
K = (1-0) / (√ 3-0) = √ 3 / 3 of linear OM
Because the tangent is perpendicular to OM
So the tangent equation k = - √ 3
And the tangent equation passes through M (√ 3,1)
Then tangent equation: Y-1 = - √ 3 (x - √ 3)
The results are as follows: √ 3x + y-4 = 0

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