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The equation of tangent passing through point P (2,3) leading circle x ^ 2 + y ^ 2-2x + 4Y + 4 = 0 is
After sorting out the equation of circle, we get (x-1) ^ 2 + (y + 2) ^ 2 = 1
It can be seen that the center of the circle is (1, - 2) and the radius r = 1
According to the characteristics of the tangent line of the circle, the distance from the center of the circle to the tangent line = the radius of the circle
Let the slope of the tangent be K, then the point oblique equation of the straight line is K
Y-3 = K (X-2)
kx-y+3-2k=0
Then the formula of distance from point to line is introduced
Just put it into the calculation
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