Calculate the surface integral ∫ (Z ^ 2 + x) dydz zdxdy, where the integral surface is Z = 1 / 2 (x ^ 2 + y ^ 2) between z = 0 and z = 2 Why is the Gauss theorem positive for a closed surface? (the normal vector of a plane is downward, and the angle between it and the z-axis is obtuse. It should be the lower side. It should be negative by using the Gauss theorem,

Didn't you notice the minus sign in - Z DXDY?
So the negative number on the bottom and the negative sign cancel each other out

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