The integral region is ball: x2 + Y2 + Z2

How can this be a difficult problem? If we do the spherical coordinate transformation, the integral region will be changed
　　　V：0≤r≤1,0≤θ≤2π,0≤φ≤π,
such
　　　∫∫∫(V)(x²+y²+z²)dxdydz
　　= ∫∫∫(V)r²rsinφdrdθdφ
　　= ∫[0,1]r³dr*∫[0,2π]dθ*∫[0,π]sinφdφ
　　= ……

RELATED INFORMATIONS

1. Who can help to find the triple integral of (XYZ). The region is the first trigram bounded by the sphere x2 + Y2 + Z2 = 1 and the coordinate axis. (where 2 is the square.) I use spherical coordinates to solve the result is 1 / 96, and the answer is 1 / 48
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