Find the tangent plane and normal equation of surface 3x ^ 2 + y ^ 2-z ^ 2 = 3 at point P (1,1,1)
The normal vector of the surface is (3x, y, - z), and the normal vector at point P is (3,1, - 1)
Tangent plane 3 (x-1) + (Y-1) - (Z-1) = 0, normal (x-1) / 3 = (Y-1) / 1 = (Z-1) / - 1
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