If y = √ 1-2x + √ 2x_ 1 + 1 / 2, find √ x2 + Y2 - √ x2 + Y2 + 2XY =?

If y = √ 1-2x + √ 2x_ 1 + 1 / 2, find √ x2 + Y2 - √ x2 + Y2 + 2XY =?

Because √ (1-2x) and √ (2x-1) appear in this formula at the same time
We know that the formula below the radical must be greater than or equal to 0
So (1-2x) > = 0, (2x-1) > = 0
So x = 1 / 2
Substituting x into the above formula, y = 1 / 2
So the value of the formula is √ x2 + Y2 - √ x2 + Y2 + 2XY = 1