If x2-2xy-y2-x + Y-1 = 0, find the value of X-Y

x²-2xy+y²-x+y-1=0
(x-y)²-(x-y)-1=0
[x-y-(1+√5)/2][x-y-(1-√5)/2]
So X-Y = (1 + √ 5) / 2 or X-Y = (1 - √ 5) / 2
The title is X & sup2; - 2XY + Y & sup2; - x + Y-1 = 0, right?

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