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x²;-2xy+y²;-x+y-1=0 (x-y)²;-(x-y)-1=0 [x-y-(1+√5)/2][x-y-(1-√5)/2] 所以x-y=(1+√5)/2或x-y=(1-√5)/2 題目是x²;-2xy+y²;-x+y-1=0吧?
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