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Given a (0,4), B (3,0), P (1,0), in the rectangular coordinate system, O is the origin, and the triangle AOB rotates m counterclockwise around point P (M is greater than 0) Less than 180, get the triangle a1ob1, make the point B1 fall on the edge of the triangle AOB, calculate the coordinates of point B1
The simple way to do this is to find a circle with the center of P passing through point B, which is the intersection of two points on line ab
The equation of a circle is (x - 1) ^ 2 + y ^ 2 = 4
The linear equation of AB is 4x + 3Y = 12
Substitute in
X^2 - 2X + 1 + (4 - 4X/3) ^2 = 4
25X^2 - 114X + 117 = 0
(25X - 39) (X - 3) = 0
X = 3 or 39/25
(X,Y) = (3,0),(39/25,48/25)
B1(39/25,48/25)
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