F (x) = sin (x + π / 3), the image of F (x) is symmetric with respect to (- 1,0), and the function is?
Let any point on a new function be (x, y)
Then the symmetric point (- 2-x, - y) of (- 1,0) is on f (x) = sin (x + π / 3)
==> -y=sin(-2-x+π/3)
==>y=sin(x+2-π/3)
RELATED INFORMATIONS
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