Let f (x) = (sinwx + coswx) ^ 2 + 2cos ^ 2wx (W > 0) have a minimum positive period of 2 π / 3 Finding the minimum positive period of W

f(x)=(sinwx+coswx)^2+2cos^2wx
=1+2sinwxcoswx+(1+cos2wx)
=sin2wx+cos2wx+2
=√2sin(2wx+π/4)+2
T=2π/2w=2π/3
vv=3/2

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