The even function y = f (x) decreases monotonically in the interval [0,4]. Compare the sizes of F (- 1), f (3 / π), f (- π)

The even function y = f (x) decreases monotonically in the interval [0,4]. Compare the sizes of F (- 1), f (3 / π), f (- π)

f(-1)=f(1)
f(-π)=f(π)
Because the even function y = f (x) decreases monotonically in the interval [0,4]
So f (3 / π) > F (1) > F (π)
So f (3 / π) > F (- 1) > F (- π)