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If the image of the function f (x) = (m-1) x2 + 2mx + 3 is symmetric about the Y axis, then the maximum and minimum values of F (x) in the interval [- 2, - 1] are respectively
f(x)=f(-x)
(m-1)x^2+2mx+3 = (m-1)(-x)^2+2m(-x)+3
m=0
f(x)=-x^2+3
fmax=2
fmin=-1
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